Engineering calculator
Voltage Divider Calculator, Output Voltage & Power Dissipation
Calculate output voltage and power dissipation for resistive voltage divider circuits. Enter Vin and two resistor values to find Vout.
How CalcMesh solves a voltage divider
A two-resistor voltage divider outputs Vout = Vin × R2 / (R1 + R2). We compute the output voltage, and the resistor value needed to hit a target, directly from this exact formula.
The result assumes negligible load current draw at the output; where a load matters we explain the correction in our methodology.
According to the U.S. National Institute of Standards and Technology, resistor tolerances of 1% to 5% are typical, so we remind you that a real divider’s output can drift several percent from the ideal figure.
Voltage Divider Guide
How It Works
A voltage divider consists of two resistors (R1 and R2) connected in series between a voltage source and ground. The output voltage is taken from the node between the resistors:
Vout = Vin × R2 / (R1 + R2)
The current through the divider is: I = Vin / (R1 + R2)
When to Use a Voltage Divider
- Sensor reading: Scale a 0-5V sensor output to 0-3.3V for a microcontroller
- Voltage measurement: Measure high voltages with a low-voltage ADC
- Transistor biasing: Set the operating point for BJT amplifiers
- Reference voltage: Create a stable reference for comparators
- Level shifting: Interface between circuits running at different voltages
Load Impedance Warning
The output voltage formula assumes no load (or infinite load resistance). When a load is connected, it appears in parallel with R2, effectively lowering the combined resistance and dropping the output voltage.
Rule of thumb: Load resistance should be at least 10× the value of R2 for the output to remain within 10% of the calculated value.
Practical Design Tips
- Use 1% tolerance resistors for precision applications
- Keep total resistance between 1k and 100k ohms
- Add a buffer (op-amp voltage follower) if driving any significant load
- Consider temperature effects on resistor values for precision work
Note: This calculator assumes ideal resistors with no load connected to the output.
Worked example, 12 V → 3.3 V sense rail
Labelled unloaded divider (not a power-supply design):
- Vin = 12 V, R1 = 10 kΩ, R2 = 3.9 kΩ.
- Vout = Vin×R2/(R1+R2) = 12×3.9/13.9 ≈ 3.37 V (near a 3.3 V ADC top).
- Divider current I = Vin/(R1+R2) ≈ 0.86 mA; P_R1≈7.5 mW, P_R2≈2.9 mW.
- If a 10 kΩ load sits on Vout, R2∥10k ≈ 2.8 kΩ and Vout falls, keep R_load ≫ R2.
After you run the numbers
What to do with the results
- Vout = Vin×R2/(R1+R2) is the open-circuit ideal; any load parallels R2 and pulls Vout down.
- Rule of thumb: R_load ≥ 10×R2 keeps the drop near the calculated value.
- Pick resistor wattage from the shown P_R1/P_R2, not from Vin alone.
- Do not use a divider as a bulk PSU, regulators/DC-DC belong there; dividers are for sensing/bias.
Methodology & Assumptions
This circuit tool rearranges textbook electrical identities (Ohm, power, divider) on the values you enter. Component tolerances are not modelled—treat outputs as design starts.
How this circuit node runs
Ohm/power/divider tools rearrange textbook electrical identities. Real components carry tolerances the page does not invent. Published domain formulas
govern the identities; when an agency updates rates or thresholds we refresh defaults
and the page lastmod.
| Input | Default | Source / authority |
|---|---|---|
| All inputs | Domain-typical defaults | Editorial methodology, CalcMesh 2026 |